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ahhh physics is killing me?
1) You pull a short refrigerator with a constant force across a greased (frictionless) floor, either with horizontal (case 1) or with tilted upward at an angle 25° (case 2). (a) What is the ratio of the refrigerator's speed in case 2 to its speed in case 1 if you pull for a certain time t? (b) What is this ratio if you pull for a certain distance d? 2) An old streetcar rounds a flat corner of radius 8.4 m, at 12 km/h. What angle with the vertical will be made by the loosely hanging hand straps?
1) heres the basic equations you'll need: i) force=mass*acceleration ii) V_final=V_initial +a*t, (V_initial = 0 m/s) iii) (V_final)^2=(V_inital)^2 +2*a*d, (again V_inital = 0 m/s) use trig to find the horizontal component of the angled pull: iv) f_horizontal= (f_total) cos (25), hint: pick a nice arbetrary force to pull the frig with like 100 N. a) use (iv) to find the two horizontal forces and plug them into (i) to find the acceleration. Then use (ii) to find final velocity in terms of everything else. compare the two (ii) equations for tug one and tug two to eachother to find the ratio. b)repeat a from above, except use (iii) instead of (ii). YOU NEED TO LEAVE ALL UNITS IN THE EQUATIONS UNTIL THE LAST STEP!!!!!!! 2) the angle can be found using trig and the vertical (g) and horizontal (centripetal) accelerations. a_centrip. = (velocity squared)/(radius). then if you use trig with g being one leg and a_centrip being the other leg of a triagle you can solve fot the angle: angle = arctangent (a_centrip / g), arctangent may also be written as tan^-1 on your calculator
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